Optimal. Leaf size=616 \[ \frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (a^2-b^2\right ) (e+f x)^3}{3 a^2 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {\left (a^2-b^2\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d}-\frac {\left (a^2-b^2\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{a^2 b d}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {2 i f^2 \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^3}-\frac {2 i f^2 \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^3}+\frac {2 i \left (a^2-b^2\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d^2}+\frac {2 i \left (a^2-b^2\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{a^2 b d^2}+\frac {i b f (e+f x) \text {Li}_2\left (e^{2 i (c+d x)}\right )}{a^2 d^2}-\frac {2 \left (a^2-b^2\right ) f^2 \text {Li}_3\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d^3}-\frac {2 \left (a^2-b^2\right ) f^2 \text {Li}_3\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{a^2 b d^3}-\frac {b f^2 \text {Li}_3\left (e^{2 i (c+d x)}\right )}{2 a^2 d^3} \]
[Out]
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Rubi [A]
time = 0.90, antiderivative size = 616, normalized size of antiderivative = 1.00, number of steps
used = 37, number of rules used = 17, integrand size = 34, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4639, 4493,
3377, 2717, 4495, 4268, 2317, 2438, 4489, 3391, 3798, 2221, 2611, 2320, 6724, 4621, 4615}
\begin {gather*} -\frac {2 f^2 \left (a^2-b^2\right ) \text {PolyLog}\left (3,\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d^3}-\frac {2 f^2 \left (a^2-b^2\right ) \text {PolyLog}\left (3,\frac {i b e^{i (c+d x)}}{\sqrt {a^2-b^2}+a}\right )}{a^2 b d^3}+\frac {2 i f \left (a^2-b^2\right ) (e+f x) \text {PolyLog}\left (2,\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d^2}+\frac {2 i f \left (a^2-b^2\right ) (e+f x) \text {PolyLog}\left (2,\frac {i b e^{i (c+d x)}}{\sqrt {a^2-b^2}+a}\right )}{a^2 b d^2}-\frac {b f^2 \text {PolyLog}\left (3,e^{2 i (c+d x)}\right )}{2 a^2 d^3}+\frac {i b f (e+f x) \text {PolyLog}\left (2,e^{2 i (c+d x)}\right )}{a^2 d^2}+\frac {2 i f^2 \text {PolyLog}\left (2,-e^{i (c+d x)}\right )}{a d^3}-\frac {2 i f^2 \text {PolyLog}\left (2,e^{i (c+d x)}\right )}{a d^3}-\frac {\left (a^2-b^2\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{a^2 b d}-\frac {\left (a^2-b^2\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{\sqrt {a^2-b^2}+a}\right )}{a^2 b d}+\frac {i \left (a^2-b^2\right ) (e+f x)^3}{3 a^2 b f}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {i b (e+f x)^3}{3 a^2 f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d} \end {gather*}
Antiderivative was successfully verified.
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Rule 2221
Rule 2317
Rule 2320
Rule 2438
Rule 2611
Rule 2717
Rule 3377
Rule 3391
Rule 3798
Rule 4268
Rule 4489
Rule 4493
Rule 4495
Rule 4615
Rule 4621
Rule 4639
Rule 6724
Rubi steps
\begin {align*} \int \frac {(e+f x)^2 \cos (c+d x) \cot ^2(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac {\int (e+f x)^2 \cos (c+d x) \cot ^2(c+d x) \, dx}{a}-\frac {b \int \frac {(e+f x)^2 \cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx}{a}\\ &=-\frac {\int (e+f x)^2 \cos (c+d x) \, dx}{a}+\frac {\int (e+f x)^2 \cot (c+d x) \csc (c+d x) \, dx}{a}-\frac {b \int (e+f x)^2 \cos ^2(c+d x) \cot (c+d x) \, dx}{a^2}+\frac {b^2 \int \frac {(e+f x)^2 \cos ^3(c+d x)}{a+b \sin (c+d x)} \, dx}{a^2}\\ &=-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {(e+f x)^2 \sin (c+d x)}{a d}+\frac {\int (e+f x)^2 \cos (c+d x) \, dx}{a}-\frac {b \int (e+f x)^2 \cot (c+d x) \, dx}{a^2}-\left (1-\frac {b^2}{a^2}\right ) \int \frac {(e+f x)^2 \cos (c+d x)}{a+b \sin (c+d x)} \, dx+\frac {(2 f) \int (e+f x) \csc (c+d x) \, dx}{a d}+\frac {(2 f) \int (e+f x) \sin (c+d x) \, dx}{a d}\\ &=\frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (1-\frac {b^2}{a^2}\right ) (e+f x)^3}{3 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {2 f (e+f x) \cos (c+d x)}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}+\frac {(2 i b) \int \frac {e^{2 i (c+d x)} (e+f x)^2}{1-e^{2 i (c+d x)}} \, dx}{a^2}-\left (1-\frac {b^2}{a^2}\right ) \int \frac {e^{i (c+d x)} (e+f x)^2}{a-\sqrt {a^2-b^2}-i b e^{i (c+d x)}} \, dx-\left (1-\frac {b^2}{a^2}\right ) \int \frac {e^{i (c+d x)} (e+f x)^2}{a+\sqrt {a^2-b^2}-i b e^{i (c+d x)}} \, dx-\frac {(2 f) \int (e+f x) \sin (c+d x) \, dx}{a d}+\frac {\left (2 f^2\right ) \int \cos (c+d x) \, dx}{a d^2}-\frac {\left (2 f^2\right ) \int \log \left (1-e^{i (c+d x)}\right ) \, dx}{a d^2}+\frac {\left (2 f^2\right ) \int \log \left (1+e^{i (c+d x)}\right ) \, dx}{a d^2}\\ &=\frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (1-\frac {b^2}{a^2}\right ) (e+f x)^3}{3 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {2 f^2 \sin (c+d x)}{a d^3}+\frac {(2 b f) \int (e+f x) \log \left (1-e^{2 i (c+d x)}\right ) \, dx}{a^2 d}+\frac {\left (2 \left (1-\frac {b^2}{a^2}\right ) f\right ) \int (e+f x) \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right ) \, dx}{b d}+\frac {\left (2 \left (1-\frac {b^2}{a^2}\right ) f\right ) \int (e+f x) \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right ) \, dx}{b d}+\frac {\left (2 i f^2\right ) \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a d^3}-\frac {\left (2 i f^2\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a d^3}-\frac {\left (2 f^2\right ) \int \cos (c+d x) \, dx}{a d^2}\\ &=\frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (1-\frac {b^2}{a^2}\right ) (e+f x)^3}{3 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {2 i f^2 \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^3}-\frac {2 i f^2 \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^3}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {i b f (e+f x) \text {Li}_2\left (e^{2 i (c+d x)}\right )}{a^2 d^2}-\frac {\left (i b f^2\right ) \int \text {Li}_2\left (e^{2 i (c+d x)}\right ) \, dx}{a^2 d^2}-\frac {\left (2 i \left (1-\frac {b^2}{a^2}\right ) f^2\right ) \int \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right ) \, dx}{b d^2}-\frac {\left (2 i \left (1-\frac {b^2}{a^2}\right ) f^2\right ) \int \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right ) \, dx}{b d^2}\\ &=\frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (1-\frac {b^2}{a^2}\right ) (e+f x)^3}{3 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {2 i f^2 \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^3}-\frac {2 i f^2 \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^3}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {i b f (e+f x) \text {Li}_2\left (e^{2 i (c+d x)}\right )}{a^2 d^2}-\frac {\left (b f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,e^{2 i (c+d x)}\right )}{2 a^2 d^3}-\frac {\left (2 \left (1-\frac {b^2}{a^2}\right ) f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (\frac {i b x}{a-\sqrt {a^2-b^2}}\right )}{x} \, dx,x,e^{i (c+d x)}\right )}{b d^3}-\frac {\left (2 \left (1-\frac {b^2}{a^2}\right ) f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (\frac {i b x}{a+\sqrt {a^2-b^2}}\right )}{x} \, dx,x,e^{i (c+d x)}\right )}{b d^3}\\ &=\frac {i b (e+f x)^3}{3 a^2 f}+\frac {i \left (1-\frac {b^2}{a^2}\right ) (e+f x)^3}{3 b f}-\frac {4 f (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d^2}-\frac {(e+f x)^2 \csc (c+d x)}{a d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d}-\frac {\left (1-\frac {b^2}{a^2}\right ) (e+f x)^2 \log \left (1-\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d}-\frac {b (e+f x)^2 \log \left (1-e^{2 i (c+d x)}\right )}{a^2 d}+\frac {2 i f^2 \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^3}-\frac {2 i f^2 \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^3}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {2 i \left (1-\frac {b^2}{a^2}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d^2}+\frac {i b f (e+f x) \text {Li}_2\left (e^{2 i (c+d x)}\right )}{a^2 d^2}-\frac {2 \left (1-\frac {b^2}{a^2}\right ) f^2 \text {Li}_3\left (\frac {i b e^{i (c+d x)}}{a-\sqrt {a^2-b^2}}\right )}{b d^3}-\frac {2 \left (1-\frac {b^2}{a^2}\right ) f^2 \text {Li}_3\left (\frac {i b e^{i (c+d x)}}{a+\sqrt {a^2-b^2}}\right )}{b d^3}-\frac {b f^2 \text {Li}_3\left (e^{2 i (c+d x)}\right )}{2 a^2 d^3}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(1905\) vs. \(2(616)=1232\).
time = 22.02, size = 1905, normalized size = 3.09 \begin {gather*} \frac {2 e f \log \left (\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a d^2}+\frac {2 f^2 \left ((c+d x) \left (\log \left (1-e^{i (c+d x)}\right )-\log \left (1+e^{i (c+d x)}\right )\right )-c \log \left (\tan \left (\frac {1}{2} (c+d x)\right )\right )+i \left (\text {Li}_2\left (-e^{i (c+d x)}\right )-\text {Li}_2\left (e^{i (c+d x)}\right )\right )\right )}{a d^3}+\frac {b e^{-i c} f^2 \csc (c) \left (2 d^2 x^2 \left (2 d e^{2 i c} x+3 i \left (-1+e^{2 i c}\right ) \log \left (1-e^{2 i (c+d x)}\right )\right )+6 d \left (-1+e^{2 i c}\right ) x \text {Li}_2\left (e^{2 i (c+d x)}\right )+3 i \left (-1+e^{2 i c}\right ) \text {Li}_3\left (e^{2 i (c+d x)}\right )\right )}{12 a^2 d^3}+\frac {\left (a^2-b^2\right ) \left (12 i d^3 e^2 e^{2 i c} x+12 i d^3 e e^{2 i c} f x^2+4 i d^3 e^{2 i c} f^2 x^3+6 i d^2 e^2 \tan ^{-1}\left (\frac {2 a e^{i (c+d x)}}{b \left (-1+e^{2 i (c+d x)}\right )}\right )-6 i d^2 e^2 e^{2 i c} \tan ^{-1}\left (\frac {2 a e^{i (c+d x)}}{b \left (-1+e^{2 i (c+d x)}\right )}\right )+3 d^2 e^2 \log \left (4 a^2 e^{2 i (c+d x)}+b^2 \left (-1+e^{2 i (c+d x)}\right )^2\right )-3 d^2 e^2 e^{2 i c} \log \left (4 a^2 e^{2 i (c+d x)}+b^2 \left (-1+e^{2 i (c+d x)}\right )^2\right )+12 d^2 e f x \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}-\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-12 d^2 e e^{2 i c} f x \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}-\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+6 d^2 f^2 x^2 \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}-\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-6 d^2 e^{2 i c} f^2 x^2 \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}-\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+12 d^2 e f x \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-12 d^2 e e^{2 i c} f x \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+6 d^2 f^2 x^2 \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-6 d^2 e^{2 i c} f^2 x^2 \log \left (1+\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+12 i d \left (-1+e^{2 i c}\right ) f (e+f x) \text {Li}_2\left (\frac {i b e^{i (2 c+d x)}}{a e^{i c}+i \sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+12 i d \left (-1+e^{2 i c}\right ) f (e+f x) \text {Li}_2\left (-\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+12 f^2 \text {Li}_3\left (\frac {i b e^{i (2 c+d x)}}{a e^{i c}+i \sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-12 e^{2 i c} f^2 \text {Li}_3\left (\frac {i b e^{i (2 c+d x)}}{a e^{i c}+i \sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )+12 f^2 \text {Li}_3\left (-\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )-12 e^{2 i c} f^2 \text {Li}_3\left (-\frac {b e^{i (2 c+d x)}}{i a e^{i c}+\sqrt {\left (-a^2+b^2\right ) e^{2 i c}}}\right )\right )}{6 a^2 b d^3 \left (-1+e^{2 i c}\right )}+\frac {\left (-3 b e^2-6 b e f x-3 b f^2 x^2-3 a d e^2 x \cos (c)-3 a d e f x^2 \cos (c)-a d f^2 x^3 \cos (c)\right ) \csc \left (\frac {c}{2}\right ) \sec \left (\frac {c}{2}\right )}{6 a b d}-\frac {b e^2 \csc (c) (-d x \cos (c)+\log (\cos (d x) \sin (c)+\cos (c) \sin (d x)) \sin (c))}{a^2 d \left (\cos ^2(c)+\sin ^2(c)\right )}+\frac {\sec \left (\frac {c}{2}\right ) \sec \left (\frac {c}{2}+\frac {d x}{2}\right ) \left (-e^2 \sin \left (\frac {d x}{2}\right )-2 e f x \sin \left (\frac {d x}{2}\right )-f^2 x^2 \sin \left (\frac {d x}{2}\right )\right )}{2 a d}+\frac {\csc \left (\frac {c}{2}\right ) \csc \left (\frac {c}{2}+\frac {d x}{2}\right ) \left (e^2 \sin \left (\frac {d x}{2}\right )+2 e f x \sin \left (\frac {d x}{2}\right )+f^2 x^2 \sin \left (\frac {d x}{2}\right )\right )}{2 a d}+\frac {b e f \csc (c) \sec (c) \left (d^2 e^{i \tan ^{-1}(\tan (c))} x^2+\frac {\left (i d x \left (-\pi +2 \tan ^{-1}(\tan (c))\right )-\pi \log \left (1+e^{-2 i d x}\right )-2 \left (d x+\tan ^{-1}(\tan (c))\right ) \log \left (1-e^{2 i \left (d x+\tan ^{-1}(\tan (c))\right )}\right )+\pi \log (\cos (d x))+2 \tan ^{-1}(\tan (c)) \log \left (\sin \left (d x+\tan ^{-1}(\tan (c))\right )\right )+i \text {Li}_2\left (e^{2 i \left (d x+\tan ^{-1}(\tan (c))\right )}\right )\right ) \tan (c)}{\sqrt {1+\tan ^2(c)}}\right )}{a^2 d^2 \sqrt {\sec ^2(c) \left (\cos ^2(c)+\sin ^2(c)\right )}} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.13, size = 0, normalized size = 0.00 \[\int \frac {\left (f x +e \right )^{2} \cos \left (d x +c \right ) \left (\cot ^{2}\left (d x +c \right )\right )}{a +b \sin \left (d x +c \right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 2541 vs. \(2 (559) = 1118\).
time = 0.62, size = 2541, normalized size = 4.12 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (e + f x\right )^{2} \cos {\left (c + d x \right )} \cot ^{2}{\left (c + d x \right )}}{a + b \sin {\left (c + d x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F(-1)]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \text {Hanged} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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[Out]
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